Gases possess characteristic critical temperature which depends upon the magnitude of intermolecular forces between the particles. Following are the critical temperatures of some gases.
$Gases$$H_2$$He$$O_2$$N_2$
$Critical \ temperature \ (K)$$33.2$$5.3$$154.3$$126$

From the above data,what would be the decreasing order of liquefaction of these gases?

  • A
    $H_2 > He > O_2 > N_2$
  • B
    $He > O_2 > H_2 > N_2$
  • C
    $N_2 > O_2 > H_2 > He$
  • D
    $O_2 > N_2 > H_2 > He$

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Similar Questions

An ideal gas cannot be liquefied because ........

At what pressure does $SO_2$ gas liquefy at room temperature?

Assertion : At critical temperature,liquid passes into gaseous state imperceptibly and continuously.
Reason : The density of liquid and gaseous phase is equal at critical temperature.

Gases can be liquefied by:

Four gas cylinders containing $He$,$N_2$,$CO_2$ and $NH_3$ gases separately are gradually cooled from a temperature of $500 \ K$. Which gas will liquefy first?
(Given $T_C$ in $K - He: 5.3, N_2: 126, CO_2: 304.1$ and $NH_3: 405.5$)

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